URI Problem 1037 – Interval solution( Bangla ) | C language

** Before watching the solution please make sure that you have tried enough **

#include <stdio.h>

int main()
    float n;
    scanf("%f", &n);
    if (n >= 0.00 && n<= 25.0000){
        printf("Intervalo [0,25]\n");
    else if (n>=25.00001 && n<=50.000000){
        printf("Intervalo (25,50]\n");
    else if (n>=50.0000001 && n<=75.000000){
        printf("Intervalo (50,75]\n");
    else if (n>=75.0000001 && n<=100.000000){
        printf("Intervalo (75,100]\n");
    else printf("Fora de intervalo\n");
    return 0;


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